help me out from these problems
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raju232007 wrote: Problem 152
triangle PQR is a right triangle..
Let PQ=x and QR=y
triangle PQR is divide into two triangles PQB & RQB
In triangle PQB
a^2+4=x^2....(1)
In triangle RQB
b^2+4=y^2....(2)
In triangle PQR
(a+b)^2=x^2+y^2..(3)
Applying 1 & 2 in 3 we get
ab=4
How you can assume triangle pqr is a right triangle?
statement 1
a=4
4b=4
b=1
PR=a+b=5
statement 2
b=1
a1=4
a=4
PR=a+b=5
Hence the ans is D