IF w+z=28 what is the value of wz?
(1) w and z are positive integers
(2) w and z are consecutive odd integers
I solved this problem by plugging in numbers and got the correct answerB
But my problem is this... the OG Book has an explanation like this:
'to look at this problem more formally, let the consecutive odd integers w and z be represented 2n+1 and 2n+3, where n is any integer. The equation in the problem can thus be expressed as... w+z= (2n+1) + (2n+3) and solved for n the result is w=2X6+1=13 and z=2X6+3=15, " i.e. B is sufficient.
What I don't understand here is that how come 2n+1 and 2n+3 express
consecutive odd integers? Because for instance 7 and 11 are consecutive odd integers but they cannot be expressed as 2n+1 and 2n+3...
I am confused, can someone explain why OG explanation is correct?
Thanks a lot
(1) w and z are positive integers
(2) w and z are consecutive odd integers
I solved this problem by plugging in numbers and got the correct answerB
But my problem is this... the OG Book has an explanation like this:
'to look at this problem more formally, let the consecutive odd integers w and z be represented 2n+1 and 2n+3, where n is any integer. The equation in the problem can thus be expressed as... w+z= (2n+1) + (2n+3) and solved for n the result is w=2X6+1=13 and z=2X6+3=15, " i.e. B is sufficient.
What I don't understand here is that how come 2n+1 and 2n+3 express
consecutive odd integers? Because for instance 7 and 11 are consecutive odd integers but they cannot be expressed as 2n+1 and 2n+3...
I am confused, can someone explain why OG explanation is correct?
Thanks a lot
