More X & Y variables
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
sudhir3127
- Legendary Member
- Posts: 829
- Joined: Mon Jul 07, 2008 10:09 pm
- Location: INDIA
- Thanked: 84 times
- Followed by:3 members
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
(1) 2 equations and 2 unknowns, but xy = -6 isn't linear, so we'll get more than 1 value: insuffcient.smclean23 wrote:If xy = -6 , what is the value of xy(x+y ) ?
(1) x – y = 5
(2) xy^2=18
Answer is B.
(2) 2 equations and 2 unknowns, but x(y^2) = 18 isn't linear. HOWEVER, we can actually divide the equation in (2) by the original to get:
x(y^2)/xy = 18/-6
y = -3
Once we know that y = -3, we know that x = 2 (from either equation). Once we have values for both x and y, we can certainly solve: statement (2) is sufficient alone, choose (B).

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
-
sudhir3127
- Legendary Member
- Posts: 829
- Joined: Mon Jul 07, 2008 10:09 pm
- Location: INDIA
- Thanked: 84 times
- Followed by:3 members
hey sorrie abt misunderstanding the question!!!..I thought its(Xy)^2.. actually its x(y)^2.. a bracket there would have eliminated the confusion,...Anyways... if that the case I go with B as well.. exactly the way stuart did it.. U need to find Y and we can do it from taking the original eqn and statement 2.
thanks stuart!!
thanks stuart!!
-
4meonly
- Legendary Member
- Posts: 891
- Joined: Sat Aug 16, 2008 4:21 am
- Thanked: 27 times
- Followed by:1 members
- GMAT Score:660(
I think B:
(1) obviously insuff.
(2) xy^2=18. Prime factorization of 18 is 2*3^2, but from the main statement we know that x or y is negative (because their product is negative). Thus, we have xyy=18=2*(-3)*(-3)
x+y=2+(-3)=-1. xy(x+y)=(-6)(-1)=6
Answer is B
(1) obviously insuff.
(2) xy^2=18. Prime factorization of 18 is 2*3^2, but from the main statement we know that x or y is negative (because their product is negative). Thus, we have xyy=18=2*(-3)*(-3)
x+y=2+(-3)=-1. xy(x+y)=(-6)(-1)=6
Answer is B
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
One thing you always need to be careful about is making assumptions in DS.4meonly wrote:I think B:
(1) obviously insuff.
(2) xy^2=18. Prime factorization of 18 is 2*3^2, but from the main statement we know that x or y is negative (because their product is negative). Thus, we have xyy=18=2*(-3)*(-3)
x+y=2+(-3)=-1. xy(x+y)=(-6)(-1)=6
Answer is B
If the ONLY thing we knew from the original was that x or y is negative, 2 wouldn't have been sufficient - because one thing we're never told is that x and y have to be integers. Even if they had to be integers, prime factorization wouldn't be enough without knowing the actual value of xy.
For example, why couldn't x = -18 and y = 1?
It's only because we know that xy = -6 (i.e. we know the actual value, not just the sign) that we can solve.

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
-
anksbhandari
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Wed Apr 30, 2008 11:05 am
- Location: India
I think D,
A is sufficient if we plug the value;
ab = -6
here ab can be = 1, -6 $ 2,-3
x - y = 5
only 2 - (-3) = 5
therefore, a = 2, and b = -3
sufficient to answer the problem
In the same way B is also sufficient
Therefore answer is D
Let me know if i am wrong
A is sufficient if we plug the value;
ab = -6
here ab can be = 1, -6 $ 2,-3
x - y = 5
only 2 - (-3) = 5
therefore, a = 2, and b = -3
sufficient to answer the problem
In the same way B is also sufficient
Therefore answer is D
Let me know if i am wrong

















