A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%
OG 18, question-166
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Let:A certain characteristic in a large population has a distribution that is symmetric about the mean (m). If 68% of the distribution lies within one standard deviation (d) of the mean, what percent of the distribution is less than m+d?
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
Mean m=10.
Standard deviation d=2.
One SD below the mean = m-d = 10-2 = 8.
One SD above the mean = m+d = 10+2 = 12.
The distribution must be symmetric about the mean of 10.
Since 68% of the distribution lies within one SD of the mean, 34% lies one SD below the mean of 10, and 34% lies one SD above the mean of 10.
The distribution looks like this:
-----16%-----8-----34%-----m=10-----34%-----12-----16%-----
Notice that 50% of the distribution is below the mean of 10, with the remaining 50% above the mean of 10, yielding the required symmetry about the mean.
Since m+d = 10+2 = 12, the portion in red is less than m+d:
16% + 34% + 34% = 84%.
The correct answer is D.
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Let's first sketch a distribution that is symmetric about the mean m.vaibhav101 wrote:A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%
Notice that m+d represents 1 unit of standard deviation ABOVE the mean
Likewise, m-d represents 1 unit of standard deviation BELOW the mean
And m+2d represents 2 units of standard deviation ABOVE the mean, etc.
ASIDE: There are infinitely many distributions that are symmetric about the mean m. The above distribution is just one.
Our goal is to determine what portion of the population is LESS THAN than m+d
First recognize that, since the distribution is symmetric about the mean m, 50% of the population is BELOW the mean, and 50% is ABOVE the mean.
Next, we're told that 68% of the distribution lies within one standard deviation d of the mean
In other words, 68% the population is BETWEEN m-d and m+d
Since the distribution is symmetric about the mean m, this 68%, is divided into two equal populations.
When we COMBINE our two findings, we see that the percentage of the population that's below m+d = 50% + 34% = 84%
Answer: D
Cheers,
Brent