Seed mixture X is 40 percent ryegrass and 60 percent
bluegrass by weight; seed mixture Y is 25%
ryegrass and 7S percent fescue. If a mixture of X and
Y contains 30 percent ryegrass, what percent of the
weight of the mixture Is X?
(A) 10%
(B) 33 1/3 %
(C) 40%
(D) 50%
(E) 662/3%
OG ans: B
help plz
OG 11th PS problem HELP please
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R=Ryegrass
B= Bluegrass
F= Fescue
x=Mixture X
y= Mixture Y
.40x= R
.60x= B
.25y= R
.75y= F
.40x+.25y=.30(x+y)
.40x+.25y=.30x+.30y
y=2x
x/x+y=?
x/3x*100=33.33%
B= Bluegrass
F= Fescue
x=Mixture X
y= Mixture Y
.40x= R
.60x= B
.25y= R
.75y= F
.40x+.25y=.30(x+y)
.40x+.25y=.30x+.30y
y=2x
x/x+y=?
x/3x*100=33.33%
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This looks like a job for weighted averages!Suteja wrote:Seed mixture X is 40 percent ryegrass and 60 percent
bluegrass by weight; seed mixture Y is 25%
ryegrass and 7S percent fescue. If a mixture of X and
Y contains 30 percent ryegrass, what percent of the
weight of the mixture Is X?
(A) 10%
(B) 33 1/3 %
(C) 40%
(D) 50%
(E) 66 2/3%
Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...
Mixture X is 40 percent ryegrass
Mixture Y is 25 percent ryegrass
Let x = the PERCENT of mixture X needed (in other words, x/100 = the proportion of mixture X needed)
So, 100-x = the PERCENT of mixture Y needed (in other words, (100-x)/100 = the proportion of mixture Y needed)
Weighted average of groups combined = 30%
Now take the above formula and plug in the values to get:
30 = (x/100)(40) + [(100-x)/100](25)
Multiply both sides by 100 to get: 30 = 40x + (100-x)(25)
Expand: 3000 = 40x + 2500 - 25x
Simplify: 3000 = 15x + 2500
So: 500 = 15x
Solve: x = 500/15
= 100/3
= 33 1/3
So, mixture X is 33 1/3 % of the COMBINED mix.
Answer: B
For more information on weighted averages, you can watch this video: https://www.gmatprepnow.com/module/gmat- ... ics?id=805
Here are some additional practice questions related to weighted averages:
- https://www.beatthegmat.com/weighted-ave ... 17237.html
- https://www.beatthegmat.com/weighted-ave ... 14506.html
- https://www.beatthegmat.com/average-weig ... 57853.html
- https://www.beatthegmat.com/averages-que ... 87118.html
Cheers,
Brent