There is something wrong here...we can combine both X and V but we still can not decide whether svx < 0 since we dont know the sign of S
and in the question stem it is given as (s^4), so it be will be POSITIVE in every case. Am I missing something here ?
svx
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pbanavara
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Source of this question please.. the OA can't be C. Like logitech says - we don't have the sign for S and more over v < 0 imples x>0 and x>0 implies v<0.
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cramya
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We dont even need the statements to know v is positive and x is negative or vice versa (may be which one is which we need the staements but it makes no difference in determining the sign of svx - one of the three variables is positive and the 2nd one of the three negative)
(s^4) (v^3) (x^7) < 0
s^4 always positive. Either v is negative , x is postive or vice versa.So we need info on s.
The question seems a little weird.
Sogmat, can u please check if everything is right?
(s^4) (v^3) (x^7) < 0
s^4 always positive. Either v is negative , x is postive or vice versa.So we need info on s.
The question seems a little weird.
Sogmat, can u please check if everything is right?
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rahulg83
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we can write ((svx)^3)s(x^4)<0
this means ((svx)^3)s<0 as x^4 is always positive
now if v<0 and x>0 implies vx<0
in anycase whether s<0 or s>0 the product will always be less than 0
(positive*negtative)^3*positive => negative*positive which is less than 0
(negative*negative)^3*positive => positive*negative which is also less than 0
so answer should be C
this means ((svx)^3)s<0 as x^4 is always positive
now if v<0 and x>0 implies vx<0
in anycase whether s<0 or s>0 the product will always be less than 0
(positive*negtative)^3*positive => negative*positive which is less than 0
(negative*negative)^3*positive => positive*negative which is also less than 0
so answer should be C
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logitech
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If (s^4) (v^3) (x^7) < 0, is svx < 0?rahulg83 wrote:we can write ((svx)^3)s(x^4)<0
this means ((svx)^3)s<0 as x^4 is always positive
now if v<0 and x>0 implies vx<0
in anycase whether s<0 or s>0 the product will always be less than 0
(positive*negtative)^3*positive => negative*positive which is less than 0
(negative*negative)^3*positive => positive*negative which is also less than 0
so answer should be C
(1) v < 0
(2) x > 0
S = +2
V = -3
X = +1
SVX = -6
S=-2
V=-3
X=+1
SVX =+6
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ronniecoleman
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whats the source ?
IMO E
We need to know the value of S to determine svx < 0
IMO E
We need to know the value of S to determine svx < 0
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