DS from gmat club

This topic has expert replies
User avatar
Legendary Member
Posts: 1077
Joined: Mon Dec 13, 2010 1:44 am
Thanked: 118 times
Followed by:33 members
GMAT Score:710

DS from gmat club

by bblast » Sun Jan 09, 2011 8:21 am
A rectangular solid box is x inches long, y inches wide and z inches tall, where x , y , and z are positive integers, exactly two of which are equal. What is the total surface area of the box?

1. One face of the box has an area of 9 square inches.
2. One face of the box has an area of 81 square inches.

OA E
Cheers !!

Quant 47-Striving for 50
Verbal 34-Striving for 40

My gmat journey :
https://www.beatthegmat.com/710-bblast-s ... 90735.html
My take on the GMAT RC :
https://www.beatthegmat.com/ways-to-bbla ... 90808.html
How to prepare before your MBA:
https://www.youtube.com/watch?v=upz46D7 ... TWBZF14TKW_
Source: — Data Sufficiency |

User avatar
Legendary Member
Posts: 543
Joined: Tue Jun 15, 2010 7:01 pm
Thanked: 147 times
Followed by:3 members

by anshumishra » Sun Jan 09, 2011 8:33 am
bblast wrote:A rectangular solid box is x inches long, y inches wide and z inches tall, where x , y , and z are positive integers, exactly two of which are equal. What is the total surface area of the box?

1. One face of the box has an area of 9 square inches.
2. One face of the box has an area of 81 square inches.

OA E
Total surface area = 2(xy+yz+zx) = ?

Statement 1:
xy = 9 -> Insufficient

Statement 2:
yz = 81 -> Insufficient

Combining 1 and 2 :
xy = 9
yz = 81
Only thing we need to find is zx = ?
yz/xy = 81/9 = 9
=> z = 9x
zx = 9x^2

Still we can't conclusively determine the sides or the expression 2(xy+yz+zx)

Hence, E

Also, using Plugging in numbers :
x= 1, y = 9, z = 9
x=3, y = 3, z = 27

xz has different values for these two pairs.
Thanks
Anshu

(Every mistake is a lesson learned )