A right circular cylinder with a radius of 2 feet and a leng

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A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2Ï€
B. 3Ï€
C. 8Ï€
D. 12Ï€
E. 24Ï€

OA C

Source: Princeton Review
Source: — Problem Solving |

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by Jay@ManhattanReview » Wed Mar 06, 2019 9:49 pm
BTGmoderatorDC wrote:Image

A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2Ï€
B. 3Ï€
C. 8Ï€
D. 12Ï€
E. 24Ï€

OA C

Source: Princeton Review
Given that the height of the cylinder is 6, the height of each of the three pieces = 6/3 = 2 feet

Thus, the volume of each of the three pieces = πr^2*h = π*2^2*2 = 8π feet^3

The correct answer: C

Hope this helps!

-Jay
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by Scott@TargetTestPrep » Thu Mar 14, 2019 5:59 am
BTGmoderatorDC wrote:Image

A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2Ï€
B. 3Ï€
C. 8Ï€
D. 12Ï€
E. 24Ï€

OA C

Source: Princeton Review
The formula for the volume of a right circular cylinder is V = π x r^2 x h; thus, the volume of the entire cylinder is:

Ï€ x 2^2 x 6 = 24Ï€ ft^3

So when it's cut into 3 equal pieces, the volume of each piece is 24Ï€/3 = 8Ï€ ft^3.

Answer: C

Scott Woodbury-Stewart
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