AAPL wrote:Of all the attendees at a dinner party, 40% were women. If each attendee arrived at the party either alone or with another attendee of the opposite GMAT, what percentage of the total number of attendees arrived at the party alone?
(1) 50% of the male attendees arrived with a woman.
(2) 25% of the attendees arriving alone were women.
The OA is D.
consider total = 100 people
From 2)
x is the number of alone people
alone women = x/4
alone men = 3x/4
From the question, we get 40 women and 60 men.
Number of men together = number of women together
=> 40 - x/4 = 60 -3x/4
=> x = 40.
Hence, the correct answer is D.
Has anyone another strategic approach to solve this DS question? Regards!
Say the percentage of men attending alone = m, the percentage of women attending alone = w, and the percentage of partners attending together = b.
Thus, 100 = m + w + b; note that among partners, b/2 would be men and b/2 would be women.
Given: w + b/2 = 40;
=> m + b/2 = 100 - 40 = 60
From w + b/2 = 40 and m + b/2 = 60, we get m - w = 20
We have to get the value of (m + w).
Let's take each statement one by one.
(1) 50% of the male attendees arrived with a woman.
50% of (m + b/2) = b/2
=> b = 2m
From b = 2m, and m + b/2 = 60, we have m = 30. From m = 30 and m - w = 20, we have w = 10.
Thus, m + w = 30 + 10 = 40. Sufficient.
(2) 25% of the attendees arriving alone were women.
25% of (m + w) = w
=> m = 3w
From m = 3w and m - w = 20, we have m = 30 and w = 10.
Thus, m + w = 30 + 10 = 40. Sufficient.
The correct answer:
D
Hope this helps!
-Jay
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