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Of a set of 25 consecutive integers beginning with 4

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by M7MBA » Sat Nov 25, 2017 8:35 am
Of a set of 25 consecutive integers beginning with 4, what is the probability that a number selected at random will be divisible by 3?

A. 13/25
B. 9/25
C. 8/25
D. 6/25
E. 3/8

The OA is C .

I don't like the probabilities questions. Experts, may you help me please?
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by [email protected] » Sat Nov 25, 2017 11:49 am
Hi M7MBA,

We're told to consider a set of 25 consecutive integers beginning with 4 (meaning the integers from 4 to 28, inclusive). We're asked for the probability that a number selected at random from this group will be divisible by 3.

The numbers divisible by 3 would be 6, 9, 12, 15, 18, 21, 24 and 27, meaning 8 out of 25 would be divisible by 3.

Final Answer: C

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by Jeff@TargetTestPrep » Mon Dec 11, 2017 7:04 am
M7MBA wrote:Of a set of 25 consecutive integers beginning with 4, what is the probability that a number selected at random will be divisible by 3?

A. 13/25
B. 9/25
C. 8/25
D. 6/25
E. 3/8
We are given that there is a set of 25 consecutive integers, starting with the number 4. Thus, the set of integers is from 4 to 28, inclusive. We need to determine how many multiples of 3 fall within that range. To do so, we can use the following formula:

# of multiples of 3 = [(largest multiple of 3 in the set - smallest multiple of 3 in the set)/3] + 1

# of multiples of 3 = [(27 - 6)/3] +1 = 21/3 + 1 = 8

Thus, the probability of selecting a multiple of 3 is 8/25.

Answer: C

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