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1) if sqrt(m) is an integer then sqrt(m)^n will be an integer because n is a positive integer - Suffexhilaration wrote:IF m and n are positive integers, is sqrt(m)^n an integer?
(1) sqrt(m) is a integer
(2) sqrt(n) is an integer
OA: A
Thanks for your help in advance.
Thanks! - the "positive" didn't hit me until now.aroon7 wrote:1) if sqrt(m) is an integer then sqrt(m)^n will be an integer because n is a positive integer - Suffexhilaration wrote:IF m and n are positive integers, is sqrt(m)^n an integer?
(1) sqrt(m) is a integer
(2) sqrt(n) is an integer
OA: A
Thanks for your help in advance.
2) sqrt(n) is an integer tells n is a perfect square and nothing else...
if m = 7 and n = 9 then sqrt(m)^n is not an integer
if m = 7 and n = 4 then sqrt(m)^n is an integer
so Insuff.
ans is A
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