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OG #11 D44

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OG #11 D44

by exhilaration » Fri Jan 23, 2009 4:30 pm
IF m and n are positive integers, is sqrt(m)^n an integer?

(1) sqrt(m) is a integer

(2) sqrt(n) is an integer

OA: A

Thanks for your help in advance.
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Re: OG #11 D44

by aroon7 » Fri Jan 23, 2009 5:40 pm
exhilaration wrote:IF m and n are positive integers, is sqrt(m)^n an integer?

(1) sqrt(m) is a integer

(2) sqrt(n) is an integer

OA: A

Thanks for your help in advance.
1) if sqrt(m) is an integer then sqrt(m)^n will be an integer because n is a positive integer - Suff
2) sqrt(n) is an integer tells n is a perfect square and nothing else...
if m = 7 and n = 9 then sqrt(m)^n is not an integer
if m = 7 and n = 4 then sqrt(m)^n is an integer
so Insuff.

ans is A
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Re: OG #11 D44

by exhilaration » Fri Jan 23, 2009 5:54 pm
aroon7 wrote:
exhilaration wrote:IF m and n are positive integers, is sqrt(m)^n an integer?

(1) sqrt(m) is a integer

(2) sqrt(n) is an integer

OA: A

Thanks for your help in advance.
1) if sqrt(m) is an integer then sqrt(m)^n will be an integer because n is a positive integer - Suff
2) sqrt(n) is an integer tells n is a perfect square and nothing else...
if m = 7 and n = 9 then sqrt(m)^n is not an integer
if m = 7 and n = 4 then sqrt(m)^n is an integer
so Insuff.

ans is A
Thanks! - the "positive" didn't hit me until now.
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