First consider (1) alone.
x<10.
For x = 1, 2, 3, 4 the values of x! + (x + 1) are 2, 5, 10, 29 respectively.
Out of these, 3 are prime and 1 is not prime.
Or (1) alone is not sufficient.
Next consider (2) alone.
For x = 2, 4, 6, 8 the values of x! + (x + 1) are 5, 29, 727, 8!+9.
The first 3 are prime but 8! + 9 will not be a prime because it will be divisible by 9.
Again nothing definite can be said.
So even (2) alone is not sufficient.
On combining we can check again with same values of 2, 4, 6 and 8 and get the same result that nothing definite can be said .
The correct answer is E.
Rahul Lakhani
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But I wanted to throw in something else...
