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Combinatorics #2

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Combinatorics #2

by papgust » Sun Oct 18, 2009 5:11 am
In how many ways can 10 identical presents be distributed among 6 children so that each child gets at least one present?

A. 15C5
B. 16C6
C. 9C5
D. 6^10
E. None of these

Solution and explanation pls?
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by papgust » Tue Oct 20, 2009 1:18 am
Can someone help me solve the prob?
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by ayashlaha » Thu Oct 29, 2009 4:36 pm
There's 1 way in which each child gets a gift

That leaves us with 4 gifts amongs 6 children. There are 15 ways to do this 6!/(4!.2!)

Thus a total of 16 ways.

However I'm not sure. Someone please confirm the official answer
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