Combinatorics #2

In how many ways can 10 identical presents be distributed among 6 children so that each child gets at least one present?

A. 15C5
B. 16C6
C. 9C5
D. 6^10
E. None of these

Solution and explanation pls?

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papgust: Community Manager; Posts: 1537; Joined: Mon Aug 10, 2009 6:10 pm; Thanked: 653 times; Followed by:252 members

by papgust » Tue Oct 20, 2009 1:18 am

Can someone help me solve the prob?

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ayashlaha: Junior | Next Rank: 30 Posts; Posts: 10; Joined: Sun Oct 25, 2009 2:09 pm; Thanked: 2 times

by ayashlaha » Thu Oct 29, 2009 4:36 pm

There's 1 way in which each child gets a gift

That leaves us with 4 gifts amongs 6 children. There are 15 ways to do this 6!/(4!.2!)

Thus a total of 16 ways.

However I'm not sure. Someone please confirm the official answer

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