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chess amateurs

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chess amateurs

by pemdas » Tue Feb 07, 2012 4:15 pm
There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?

A 10
B 20
C 40
D 60
E 120

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by Anurag@Gurome » Tue Feb 07, 2012 9:39 pm
pemdas wrote:There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?

A 10
B 20
C 40
D 60
E 120

made up
There are 5 chess amateurs and each chess amateur plays with exactly 4 other amateurs. So, number of ways of playing a participant games = 5 * 4 = 20
Since each game will have 2 amateurs in each game, so total number of chess games possible to be played in the tournament = 20/2 = 10

The correct answer is A.
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