chess amateurs

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pemdas: Legendary Member; Posts: 1084; Joined: Fri Apr 15, 2011 2:33 pmFollowed by: 21 members; Thanked: 158 times

by pemdas » Tue Feb 07, 2012 4:15 pm

There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?

A 10
B 20
C 40
D 60
E 120

made up

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Source: Beat The GMAT — Problem Solving | Tue Feb 07, 2012 4:15 pm

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Anurag@Gurome: GMAT Instructor; Posts: 3835; Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members; Location: Milpitas, CA; Thanked: 1854 times; GMAT Score:770

by Anurag@Gurome » Tue Feb 07, 2012 9:39 pm

pemdas wrote:There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?

A 10
B 20
C 40
D 60
E 120

made up

There are 5 chess amateurs and each chess amateur plays with exactly 4 other amateurs. So, number of ways of playing a participant games = 5 * 4 = 20
Since each game will have 2 amateurs in each game, so total number of chess games possible to be played in the tournament = 20/2 = 10

The correct answer is A.

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