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can you please explain this?

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by j5makk » Mon Oct 11, 2010 4:01 am
n here is exponent and it has negative sign sometimes

Each of the following equations has at least one solution EXCEPT

-2>n = (-2)>-n

2>-n = (-2)>n

2>n = (-2)>-n

(-2)>n = -2>n

(-2)>-n = -2>-n
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by kmittal82 » Mon Oct 11, 2010 4:19 am
>Each of the following equations has at least one solution EXCEPT
Isn't n=0 a solution for all of them?
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by Jim@Grockit » Mon Oct 11, 2010 6:27 am
kmittal82 wrote:>Each of the following equations has at least one solution EXCEPT
Isn't n=0 a solution for all of them?
That's the conclusion I came to . . . perhaps something is missing from the notation?
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by Viktri » Wed Oct 13, 2010 9:57 pm
The only one with no solution is (-2)n = -2n

You cannot find the value of n because 1 term = 1 term

For the other equations, the n's can be grouped on one side and the #s on the other, allowing for someone to solve for n
j5makk wrote:Each of the following equations has at least one solution EXCEPT

-2n = (-2)-n

2-n = (-2)n

2n = (-2)-n

(-2)n = -2n

(-2)-n = -2-n
what is the logic and how to tackle such problems
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