Each of the following equations has at least one solution EXCEPT
-2n = (-2)-n
2-n = (-2)n
2n = (-2)-n
(-2)n = -2n
(-2)-n = -2-n
what is the logic and how to tackle such problems
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can you please explain this?
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Jim@Grockit
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That's the conclusion I came to . . . perhaps something is missing from the notation?kmittal82 wrote:>Each of the following equations has at least one solution EXCEPT
Isn't n=0 a solution for all of them?
The only one with no solution is (-2)n = -2n
You cannot find the value of n because 1 term = 1 term
For the other equations, the n's can be grouped on one side and the #s on the other, allowing for someone to solve for n
You cannot find the value of n because 1 term = 1 term
For the other equations, the n's can be grouped on one side and the #s on the other, allowing for someone to solve for n
j5makk wrote:Each of the following equations has at least one solution EXCEPT
-2n = (-2)-n
2-n = (-2)n
2n = (-2)-n
(-2)n = -2n
(-2)-n = -2-n
what is the logic and how to tackle such problems
