Number Properties w/ Remainders

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by wingsoffire » Sat Sep 03, 2011 4:10 am
yes Its D . We will need both to arrive at any conclusion

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by prateek_guy2004 » Sat Sep 03, 2011 1:25 pm
I messed up with both the statements in order to prove them wrong.....Statements are always right one should not waste time to prove it wrong..

statements 1 and 2 both sufficient hence D
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by prashant misra » Sat Sep 24, 2011 9:44 am
the answer is option D

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by parul9 » Sat Oct 15, 2011 10:38 am
It's D!

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by BioBloggerAmyP » Tue Nov 01, 2011 6:03 pm
How does statement 2 work out?

Plus in:

x = 15, therefore according to statement II x/12 = 1 R 3 and x/6 = 2 R 3
x = 18, therefore according to statement II x/12 = 1 R 6 and x/6 = 3 R 0

Therefore, as you change x, the remainder of x/6 does NOT remain consistent with the remainder of x/12. Isn't the answer A (Statement I alone is suffient).

Please explain why statement II is sufficient on its own.

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by immaculatesahai » Sun Dec 18, 2011 1:07 am
D it is !!!

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by Sharma_Gaurav » Mon Jan 09, 2012 2:42 pm
straight D

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by NehaShethia » Tue Jan 17, 2012 11:00 am

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by ronnie1985 » Fri Feb 03, 2012 10:30 am
Q. R(x/6) = ?
S1. R(x/2) = 1
R(x/3) = 0
x = 3*(2n+1) = 6n+3
R(x/6) = R((6n+3)/6) = 3
Sufficient
S2. R(x/12) = 3
x = 12n+3
R(x/6) = R((12n+3)/6) = 3
Sufficient
(D) is answer
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by Rastis » Wed Mar 21, 2012 6:10 am
Stuart,

Why did you pick "3" for statement 2?

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by Ganesh hatwar » Mon Jul 23, 2012 5:37 am
aznmexicana wrote:What is the remainder when the positive integer x is divided by 6?

1) When x is divided by 2 the remainder is 1, and when x is divided by 3, the remainder is 0
2) When x is divided by 12 the remainder is 3
D?

A LCM 6
B Factor of 6

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by surmilsehgal » Tue Jul 31, 2012 11:09 pm
the answer is C

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by rajeshsinghgmat » Wed Feb 06, 2013 4:34 am
D the answer.

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by ritzzzr » Tue Feb 12, 2013 9:25 pm
Plug in numbers for each statement and you will find that both statement are sufficient independently.

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by ndqv » Wed Sep 04, 2013 6:06 am
1) x = 2m+1 = 3n
Try m = 3k, 3k+1 & 3k+2 => m = 3k+1
=> x = 6k+3 => remainder = 3

2) x = 12k+3 = 6(2k)+3 => remainder = 3

Choose D