yes Its D . We will need both to arrive at any conclusion

I messed up with both the statements in order to prove them wrong.....Statements are always right one should not waste time to prove it wrong..

statements 1 and 2 both sufficient hence D

the answer is option D

It's D!

How does statement 2 work out?

Plus in:

x = 15, therefore according to statement II x/12 = 1 R 3 and x/6 = 2 R 3
x = 18, therefore according to statement II x/12 = 1 R 6 and x/6 = 3 R 0

Therefore, as you change x, the remainder of x/6 does NOT remain consistent with the remainder of x/12. Isn't the answer A (Statement I alone is suffient).

Please explain why statement II is sufficient on its own.

D it is !!!

straight D

D.

Q. R(x/6) = ?
S1. R(x/2) = 1
R(x/3) = 0
x = 3*(2n+1) = 6n+3
R(x/6) = R((6n+3)/6) = 3
Sufficient
S2. R(x/12) = 3
x = 12n+3
R(x/6) = R((12n+3)/6) = 3
Sufficient
(D) is answer

Stuart,

Why did you pick "3" for statement 2?

aznmexicana wrote:What is the remainder when the positive integer x is divided by 6?

1) When x is divided by 2 the remainder is 1, and when x is divided by 3, the remainder is 0
2) When x is divided by 12 the remainder is 3

D?

A LCM 6
B Factor of 6

the answer is C

D the answer.

Plug in numbers for each statement and you will find that both statement are sufficient independently.

1) x = 2m+1 = 3n
Try m = 3k, 3k+1 & 3k+2 => m = 3k+1
=> x = 6k+3 => remainder = 3

2) x = 12k+3 = 6(2k)+3 => remainder = 3

Choose D