7 when multiplied by 7 follows a sequence to the end which repeats.

7=7
7^2=49
7^3=343
7^4=2041
7^5=7

so 7,9,3,1 keeps on repeating. given x is a positive integer. let it be 1 7^15 will end with 3 and +3 will give u a 6 to last. so 1 will be the remainder.

In a problem such as this that seems to require lots of time consuming calculation it is best to look for a pattern in the numbers:

7^1 = 7
7^2 = 49
7^3 = 343
7^4 = 2401
7^5 = 16807

Then you can see the pattern in the units digit. we know that when you divide by 5 the remainder will be any units digit between 1 and 4 or 5 minus the units digit between 6 and 9.

So we need to find the units digit. There is no definition for x so we can assume it can be 1 - then you are looking for 7^15 + 3 - use the pattern above to simply count to 15 and discover that the units digit of 7^15 will be 3 therefore the units digit of the equation will be 6. when you divide a number with a 6 as a units digit by 5 you will get a remainder of 1. Thus the answer is 1.

But if you take x = 2 or 3, etc... doesn't the answer change?