BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Number Properties

Expert replies
by Aman verma » Tue Aug 09, 2011 8:57 am
Q: If 2^n can exactly divide P! such that the quotient is an odd positive integer , then the value of n which is NOT possible is:

I. 43

II. 44

III.45


a) I only

b) II only

c) III only

d) I and III both

e) I, II and III
800. Arjun's-Bird-Eye
Join the discussion
Source: — Problem Solving |

by GmatKiss » Tue Aug 09, 2011 9:40 am
i feel some info is missing on P, not sure though!
Join the discussion

by sharmishtha_goel » Tue Aug 09, 2011 11:13 am
IMO E.
Join the discussion

by Aman verma » Tue Aug 09, 2011 11:17 am
sharmishtha_goel wrote:IMO E.
How ?
800. Arjun's-Bird-Eye
Join the discussion

by sharmishtha_goel » Tue Aug 09, 2011 11:42 am
Aman verma wrote:
sharmishtha_goel wrote:IMO E.
How ?

for 50! , n = 47
48! , n = 46
47! , n = 42
46! , n = 42


If we take the factorial of a number greater than 51 n > 47
For a number less than 46 , n < 42
Join the discussion

by GmatKiss » Tue Aug 09, 2011 12:56 pm
Not able to follow, can u pls explain in detail
Join the discussion

by Aman verma » Thu Aug 11, 2011 4:31 am
GmatKiss wrote:Not able to follow, can u pls explain in detail
Now the highest power of 2 that can exactly divide 50! is 47, hence n=47,
Similarly the highest power of 2 that can exactly divide 49! & 48! is 46,
the the highest power of 2 that can exactly divide 47! & 46! is 42
Now if we take the factorial of a number greater than 51, then n > 47
For a number less than 46 ,then n < 42.Hence OA[spoiler]e)[/spoiler]

I will appreciate if anybody could suggest a better approach.
800. Arjun's-Bird-Eye
Join the discussion

by GmatKiss » Thu Aug 11, 2011 5:17 am
How p is considered to be 50, 49 and so on!
Join the discussion

by sharmishtha_goel » Thu Aug 11, 2011 6:17 am
Aman verma wrote:
GmatKiss wrote:Not able to follow, can u pls explain in detail
Now the highest power of 2 that can exactly divide 50! is 47, hence n=47,
Similarly the highest power of 2 that can exactly divide 49! & 48! is 46,
the the highest power of 2 that can exactly divide 47! & 46! is 42
Now if we take the factorial of a number greater than 51, then n > 47
For a number less than 46 ,then n < 42.Hence OA[spoiler]e)[/spoiler]

I will appreciate if anybody could suggest a better approach.

HI,

This approach is the simplest :) ....i will elaborate so that you can understand the logic behind it.

10! = 1.2.3.4.5.6.7.8.9.10
To calculate the highest power of 2 that can divide 10! , first count the number or even numbers.
10/2 = 5 , i.e. 2^5 completely divides 10!
Notice that of the 5 even numbers ( 2 4 6 8 10) 4 and 8 have more than 1 power of 2.
To calculate the highest power of 2^2 i.e 4
10 / 4 = 2 (quotient only)
To calculate the highest power of 2^3 i.e 8
10 / 8 = 1 .
Adding up 5 + 2 + 1 = 8 i.e. 2^8 divides 10! completely giving you an odd quotient or you can say that the highest power of 2 in factorial 10 is 8 .
cross check : 1.2.3.4.5.6.7.8.9.10
1.2.3.2^2.5.2.3.7.2^3.9.2.5
1.2^(1+2+1+3+1).3.5.3.7.9.5
1.2^8.3.5.3.7.9.5

Hope that helps.
Join the discussion