Hi,
We have the following facts.
- 20 parents
- 5 days to choose from (Mo, Tu, We, Th, Fr)
- Each parent will select maximum 1 day
- More people chose "Mo" than "Tu".
- No restriction on the parent/day distribution or the maximum parents per day!
- There is a possibility that some days were not chosen by any parents (since the question already asks whether Friday was selected).
Now, if i interpret statement 1, "None of the five days was chosen by more than 5 parents", then IMO it will mean that:
- More than 5 parents didn't choose any of these five days
- More than five means at least 6.
- That leaves us with a maximum of 14 parents.
- 14 Parents will choose from 5 days.
- Option 1: We can distribute 14 parents accross 4 days without including Friday and still conform to the fact that more poeple chose "Mo" than "Tu": Mo (6), Tu (5), We (2), Th (1), Fr(0)
- Option 2: We can also eliminate "Th" and add 1 more vote to "We": Mo (6), Tu (5), We (3), Th (0), Fr (0)
- Option 3: we can move that vote to Friday instead: Mo (6), Tu (5), We (1), Th (1), Fr (1)
- So, my conclusion is that statement 1 is not sufficient.
For statement 2, more people also chose Monday than Wednesday, then we will distribute 20 parents across 5 days:
- Option 1: Mo (10), Tu (5), We (3), Th (2), Fr(0) -> Friday can be ignored
- Option 2: Mo (10), Tu (5), We (3), Th (1), Fr(1) -> Friday can be selected
.. then again.. statement 2 is not sufficient.
Combining both statements will tell us that at most 14 parents will chose from 5 days and Monday will be chosen more than Tuesday and more than Wednesday separately .. not more than both of them combined. So, options 2 and 3 from statement 1 can still give us the same result.
Hence, IMO it should be E.
