Number properties

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 301
Joined: Tue Apr 22, 2008 6:07 am
Thanked: 2 times

Number properties

by beater » Thu Jan 15, 2009 12:26 pm
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?

a) 180
b) 196
c) 286
d) 288
e) 324
Source: — Problem Solving |

User avatar
Community Manager
Posts: 1049
Joined: Sun Apr 06, 2008 5:15 pm
Location: Pittsburgh, PA
Thanked: 113 times
Followed by:27 members
GMAT Score:710

by dmateer25 » Thu Jan 15, 2009 12:56 pm
Hundereds Digit, Tens Digit, Ones Digit

_ _ _

The numbers that are odd and do not contain the digit 5:

The hundreds digit can be any digit from 1 to 9 but it cannot be 5. So there are a total of 8 possibilities.

The tens digit can be any digit from 0 to 9 but it cannot be 5. So there are a total of 9 possibilities.

The ones digit must be odd so it can be 1, 3, 7, or 9 (it cannot be 5). So there are a total of 4 possibilities.

8 x 9 x 4 = 288

Junior | Next Rank: 30 Posts
Posts: 28
Joined: Sun Nov 02, 2008 12:35 pm
Thanked: 7 times

by sachinkr » Thu Jan 15, 2009 1:06 pm
Total no of Odd integers between 100 and 1000 = 450.

No of odd integers containing 5:
First, start with 501-599. total no of odd integers containing 5 = 50.

Next take number between 100-200.
Total number of odd integers containing 5 = 14 ( 5 between 150-159 and 10 between 100-200, subtract 1 as we have double counted 155).
So between 100-1000, total number of odd integers containing 5 excluding 500-599 = 14 * 8 = 112.

Therefore, total number of odd integers without 5 digit = 450-50-112 = 288.
Ans (D)