We are given xyz > 0
we need to find whether xy^2z^3>0.
y^2 is always positive. x and z^3 can be both nagative and positive, depending on the value of x and z.
A. Y > 0 , the xyz > o : x and y has to be either both positive or both nagative. Hence
X and z^3 are of same sign. hence sufficient.
B. X > 0, xyz>0 : y and z has to be either both nagative or both positive.
Y^2 is always positive.
Z^3 can be positive or nagative. - the value of z will determine the inequality ( xy^2z^3>0) in this case.
this is insufficient.
hence A.
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