Assuming (2^x/y) = (2^(x/y)),
If y!=0, Is 2^(x*x/y)< 1?
1). x>y
If x = 4 and y = 2, then 2^(x*x/y) = 2^(8) > 1
If x = 4 and y = -2, then 2^(x*x/y) = 2^(-8) < 1
If x = 0 and y = -2, then 2^(x*x/y) = 2^(0) = 1
Hence Insufficient!
If x = 4 and y = -2, then 2^(x*x/y) = 2^(-8) < 12). y< 0
If x = 0 and y = -2, then 2^(x*x/y) = 2^(0) = 1
Hence Insufficient!
From 1 and 2
If x = 4 and y = -2, then 2^(x*x/y) = 2^(-8) < 1
If x = 0 and y = -2, then 2^(x*x/y) = 2^(0) = 1
Hence Insufficient!
IMO E
