let x = 10a + b and
let y = 10c + d, then the question can be rephrased to 'What is the value of |a-c| ?
x-y = 10(a-c) + (b-d) = 271). x-y=27
10(a-c) + (b-d) = 27 (We know -9<b-d<9)
a-c = 2, b-d = 7 and a-c = 3, b-d = -3 are the solutions.
Insufficent!
b-d > 3 so (a-c) can be anything2). Units' digit of x minus the units' digit of y is greater than 3
Insufficent!
From 1 and 2
a-c = 2, b-d = 7 Hence sufficient C=[/spoiler][/quote]












