Is there a quick way to do this problem using number prop? (oops wrong forum. i can't move this. sorry)
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[email protected] wrote:Hi all,
I been working down the list of problems and I cant seem to figure out how the first statement is NOT sufficient.
If (x^3+x)/4 is an integer, then it would follow that x^3/4 + x/4 is an integer. If X is odd, the previous statement cant be an integer therefore forcing x to be even and statement 1 sufficient, right?
But that's not *all* it means. If you rephrase the statement "x^3 + x is divisible by 4" as "x^3 + x is even", you're losing a lot of information, so much information that you'll get the wrong answer here.Brian@VeritasPrep wrote:
So for this problem, statement 1 tells us that x^3 + x is divisible by 4. Well, that means that it's even.
No, this is not the case. You can see this easily enough by taking a very simple example. If I ask if x is even, and tell you that x + x is divisible by 4, then 2x must be divisible by 4, so x must be divisible by 2. You would get the wrong answer if you rephrased the statement 'x + x is divisible by 4' as 'x + x is even', since then you would think x might be odd.Brian@VeritasPrep wrote:
I think the biggest key here is to recognize up front that the question is asking "is x EVEN?". From there, "...divisible by 4"; "...divisible by 6" and statements like that are really only worthwhile to you as indications of even or odd, so you don't have to do the algebra...you can just test the number properties.
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