rohanberi wrote:On the number line, if the number k is to the left of the number c, is the product kt to the right of t ?

(1) t < 0
(2) k < 1

If the number k is to the left of the number c, on the number line, then k < c; and we know nothing about the nature of k and t to decide on whether k t > t or not. I see no reason why c is mentioned in the question. If this is not typo, then answer to the DS is doubtlessly [spoiler]E[/spoiler]; because t < 0 could include negative fractions too and k < 1 could include positive fractions as well as all negative numbers too.

And if it's typo, then I guess the right wordings would have been "the number k is to the left of the number t", and in that case statement (1) alone would have been sufficient to answer, because we already knew k < t and hence k < t < 0, and the product k t would have been positive thus making us believe that YES k t > t. Statement (2) alone is still not sufficient, and the answer to the DS would have been [spoiler]A[/spoiler].

Its a typo only.

Appreciate your help.

As per my calculation C shud b the ans..
both the statements together bring kt to right of t...

please provide values for which it doesnt..

gauravhasija wrote:As per my calculation C shud b the ans..
both the statements together bring kt to right of t...

please provide values for which it doesnt..

Hi Gaurav,

Question's supposition says k to the left of t.

First assumption says, t < 0.

Now, if t <0 , k < 0. That is both k and t are -ve.
And multiplying these two -ve numbers will give us a + ve number.
Hence, kt will be right of t on number line.

Hence, A is sufficient.

Second assumption says, k < 1

Now, k<1 doesn't tell us whether what will be the sign for k and t.

Hence, B is insufficient.

Therefore, Answer is A.

Hope that helps.

@Rohanberi

Can you please rectify the error in the question?

On the number line, if the number k is to the left of the number c, is the product kt to the right of t