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Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
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by devp » Fri May 16, 2008 6:46 am
Well here is the ans:
1. xyz < 0 suggests only one of them is -ve.
2. xy <0 suggests x and y lies on two sides of the origin or zero.

So lets draw the number line, and add both the constraints.

|-----------X--------------------------0-----------Y---------------------------------|
Now Z has to be positive. So Z can lie between 0 and Y or beyond Y. But it cannot be beyond Y as XY will be less than XZ. Even if you revert the picture the logic remains the same. So C.
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by mandy12 » Fri May 16, 2008 7:13 am
Well here is the ans:
1. xyz < 0 suggests only one of them is -ve.
2. xy <0 suggests x and y lies on two sides of the origin or zero.

So lets draw the number line, and add both the constraints.

|-----------X--------------------------0-----------Y---------------------------------|
Now Z has to be positive. So Z can lie between 0 and Y or beyond Y. But it cannot be beyond Y as XY will be less than XZ. Even if you revert the picture the logic remains the same.

Till this point I agree with devp but ---

The answer should be E. coz in the above figure I can interchange the positions of X and Y
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Isn't the answer E?

by jaspire » Fri May 16, 2008 7:08 pm
I also think the answer is E.
jaganbravo, Can you confirm?
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by moneyman » Sat May 17, 2008 8:47 am
I feel the answer is B
Maxx
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by netigen » Sat May 17, 2008 1:47 pm
Ans should be E

From B we know that either X or Y is negative
From A Given that X or Y is negative we know that Z is +ve

X | Y | Z
-------------
+ | - | + Z can be between X and Y or it can be on the right of X so not between X and Y

- | + | + Z can only be between X and Y

hence insufficient.
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