BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Linear problem

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 am
Thanked: 85 times
Followed by:3 members

by clock60 » Sat May 15, 2010 1:01 pm
dkumar.83 wrote:Image
one possible way to solve is to adopt the problem to smth old one
say scale S=axis x and x1=30, x2=60 (on x-y plane)
R scale =axis y y1=6, and y2=24
find the slope=(y2-y1)/(x2-x1)=(24-6)/(60-30)=3/5
function is linea 3/5=(y-24)/(100-60)=48, where y corresponds to the measurement on R scale
i got 48-C
Top
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 am
Thanked: 173 times
Followed by:2 members
GMAT Score:710

by gmatmachoman » Sat May 15, 2010 1:08 pm
Linear equation is of the form

y= m*x + C

Let Y belong to R scale & X belong to S scale

6= m*30 +C ----eq 1

24= m*60 +C ----eq 2

solve for m & C

we get m=3/5 & c= -12

Substitute these values in the "required " eqn as:

R scale : m* S +C
: 3/5 *100 +(-12)
:60-12
:48

Solved!!
Top
User avatar
GMAT Instructor
Posts: 3225
Joined: Tue Jan 08, 2008 2:40 pm
Location: Toronto
Thanked: 1710 times
Followed by:614 members
GMAT Score:800

by Stuart@KaplanGMAT » Sat May 15, 2010 7:13 pm
Hi!

Here's an explanation from an older post (a search of "r scale" found the old thread).

https://www.beatthegmat.com/pls-help-t12930.html
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Top
Post new topic Post Reply
• Page 1 of 1