Not sure of the solution

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Not sure of the solution

by [email protected] » Thu Jan 30, 2014 6:19 pm
Hi Experts,

For integers x and y, is x+y even?

(1) x^2−y^2 is even

(2) x−y is even

I feel the answer should be E but the answer given is D

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by GMATGuruNY » Thu Jan 30, 2014 9:49 pm
[email protected] wrote:Hi Experts,

For integers x and y, is x+y even?

(1) x^2−y^2 is even

(2) x−y is even

I feel the answer should be E but the answer given is D
Statement 1: x² - y² is even
Case 1: x² - y² = even - even.
Here, x and y must both be even.
In this case, x+y = even + even = even.

Case 2: x² - y² = odd - odd.
Here, x and y must both be odd.
In this case, x+y = odd + odd = even.

Since x+y is even in both cases, SUFFICIENT.

Statement 2: x-y is even
Case 1: x-y = even - even
In this case, x+y = even + even = even.

Case 2: x-y = odd - odd
In this case, x+y = odd + odd = even.

Since x+y is even in both cases, SUFFICIENT.

The correct answer is D.
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