The sum of the digits of [(10^x)^y]-64=279. What is the value of xy
A. 28
B. 29
C. 30
D. 31
E. 32
xy is positive integer
Ans-E
A. 28
B. 29
C. 30
D. 31
E. 32
xy is positive integer
Ans-E
Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.
See classesLearn live with an expert or move at your own pace. Every option includes the complete TTP study system.
Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.
with Josh Braslow, 20+ years in test prep
Self-paced EA prep. Study on your schedule.
with
Complete access from day one. Study on your schedule.
Sorry, I was confused for a second because I didn't see a definition of n.theCodeToGMAT wrote:[(10^x)^y]-64=279
To find: xy
10^xy - 64 = 279
Let xy = 2 ==> 36 ==> Sum = 9
Let xy = 3 ==> 936 ==> Sum = 18
Let xy = 4 ==> 9936 ==> SUm = 27
So, using formula for AP
9 + (n-1)9 = 279
9n = 279
n = 31
So, 31+1 32
[spoiler]{E}[/spoiler]
No, I just used the formula for AP term==> a + (n-1)dkackerarnav wrote:Shouldn't that term in bold above be n-2, by the pattern?theCodeToGMAT wrote:[(10^x)^y]-64=279
To find: xy
10^xy - 64 = 279
Let xy = 2 ==> 36 ==> Sum = 9
Let xy = 3 ==> 936 ==> Sum = 18
Let xy = 4 ==> 9936 ==> SUm = 27
So, using formula for AP
9 + (n-1)9 = 279
9n = 279
n = 31
So, 31+1 32
[spoiler]{E}[/spoiler]
Edit[email protected] wrote:Hi Mathsbuddy,
You made a conceptual math error in your work. Remember that we have to add up the digits in the calculation. When you change the calculation (by turning - 64 into "-100 +36"), you're changing the digits. Unless you do the necessary steps to "undo" those changes later, you're going to end up with the wrong power of 10.
GMAT assassins aren't born, they're made,
Rich