If x is not equal to 0, is |x| less than 1? Is |x| < 1 => is -1 < x < 1 ?
(1) x/|x| < x
Multiply |x| to both sides as |x| > 0, we get x < x|x| => x > 1 and -1 < x <0
In sufficient
(2) |x| > x
=> x < 0
[spoiler]Insufficient.
joining the two statements, you get -1 < x < 0, which answers the question ! [/spoiler]
Hence Option C
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neelgandham
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Last edited by neelgandham on Wed Oct 19, 2011 3:44 am, edited 2 times in total.
Anil Gandham
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Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
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neelgandham
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My bad! I missed a condition. I have edited the post now!adi_800 wrote:OA is not A
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
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Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
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Statement (1) x/|x| < xadi_800 wrote:If x is not equal to 0, is |x| less than 1?
(1) x/|x| < x
(2) |x| > x
X = 2 --> x/|x| < x --> TRUE --> |x| < 1 is NO
X = -1/4 ---> x/|x| < x --> -1 < -1/4 --> TRUE --> |x| < 1 is YES
So INSUFFICIENT...
Statement (2)
|x| > x
|x| is always greater than x only if x is negative which is a negative number or negative fraction
If x = -20 --> |x| > x correct and |x| < 1 is NO
If x = -1//4 --> |x| > x correct and |x| <1 is YES
So we have two answers so insufficient...
If we both combine the statements we can take x = -1/4 only which will satisfy both the statements...so answer is C.....Is this answer correct???? Plz post the answer... thanks...
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