Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

no of parallelograms??

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Legendary Member
Posts: 727
Joined: Sun Jun 08, 2008 9:32 pmFollowed by: 1 member
Thanked: 8 times
by umaa » Tue Jul 08, 2008 9:29 pm
The number of parallelograms that can be formed from a set of FOUR parallel straight line intersecting a set of THREE parallel straight lines=?

Options are,

a. 9
b. 12
c. 6
d. 18
Top
Join the discussion
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pmFollowed by: 1 member
Thanked: 15 times

Re: no of parallelograms??

by amitdgr » Wed Jul 09, 2008 1:36 am
umaa wrote:The number of parallelograms that can be formed from a set of FOUR parallel straight line intersecting a set of THREE parallel straight lines=?

Options are,

a. 9
b. 12
c. 6
d. 18
Is the OA c.6 ??


Amit
You do not have the required permissions to view the files attached to this post.
Top
Join the discussion
Legendary Member
Posts: 727
Joined: Sun Jun 08, 2008 9:32 pmFollowed by: 1 member
Thanked: 8 times

by umaa » Wed Jul 09, 2008 1:48 am
No my friend. I've got the same answer. The answer is 18 (d).
Top
Join the discussion
User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pmFollowed by: 1 member
Thanked: 15 times

by amitdgr » Wed Jul 09, 2008 2:16 am
umaa wrote:No my friend. I've got the same answer. The answer is 18 (d).
18 ? oh .. :shock:

how is it 18 ?


Amit
Top
Join the discussion

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2623
Joined: Mon Jun 02, 2008 3:17 amFollowed by: 355 members
Location: Montreal
Thanked: 1090 times
GMAT Score:780

by Ian Stewart » Wed Jul 09, 2008 4:43 am
You're only counting the six smallest parallelograms in the picture (nice picture, by the way!). If, for example, you take all six of the small parallelograms and consider it to be one shape, you get one large parallelogram. And there are many others:

6 parallelograms that measure 1 across, 1 vertical (smallest possible)
3 parallelograms that are 2 across and 1 vertical
4 parallelograms that are 1 across and 2 vertical
2 parallelograms that are 2 across and 2 vertical
2 parallelograms that are 1 across and 3 vertical
1 parallelogram that is 2 across and 3 vertical (all of them together)

Hope the terminology makes sense. That's a total of 18 parallelograms.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Top
Join the discussion
Legendary Member
Posts: 727
Joined: Sun Jun 08, 2008 9:32 pmFollowed by: 1 member
Thanked: 8 times

Thanks

by umaa » Wed Jul 09, 2008 5:02 am
Thanks Ian. I missed that out. :lol:
Top
Join the discussion
User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pmFollowed by: 1 member
Thanked: 15 times

by amitdgr » Wed Jul 09, 2008 5:05 am
Ian Stewart wrote:You're only counting the six smallest parallelograms in the picture (nice picture, by the way!). If, for example, you take all six of the small parallelograms and consider it to be one shape, you get one large parallelogram. And there are many others:

6 parallelograms that measure 1 across, 1 vertical (smallest possible)
3 parallelograms that are 2 across and 1 vertical
4 parallelograms that are 1 across and 2 vertical
2 parallelograms that are 2 across and 2 vertical
2 parallelograms that are 1 across and 3 vertical
1 parallelogram that is 2 across and 3 vertical (all of them together)

Hope the terminology makes sense. That's a total of 18 parallelograms.
Thanks for explaining it Ian :)

Ian Stewart wrote: (nice picture, by the way!).
:lol:


Amit
Top
Join the discussion
User avatar
Master | Next Rank: 500 Posts
Posts: 246
Joined: Mon May 19, 2008 7:34 am
Location: Texaco Gas Station
Thanked: 7 times

by cubicle_bound_misfit » Wed Jul 09, 2008 10:18 pm
you need to choose 2 parallel lines along with 2 vertical line.

2 parallel lines can be chosen from 4 parallel line in 4C2 ways .
2 vertical lines can be chosen from 3 vertical line in 3C2 ways

together the condition can be chosen in 4C2 * 3C2 ways ==18.

Hope that helps.

Regards,
Cubicle Bound Misfit
Top
Join the discussion