Are all of the terms in Set A equal?

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by GMATGuruNY » Thu Dec 06, 2012 1:42 am
himu wrote:Are all of the terms in List A equal?

The sum of all 14 terms in List A is 98.
The sum of any 3 terms in List A is 21.
Statement 1: The sum of all 14 terms in List A is 98.
Average of all 14 terms = 98/14 = 7.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, in which case all 14 terms are equal.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6, 8, in which case all 14 terms are NOT equal.
INSUFFICIENT.

Statement 2: The sum of any 3 terms in List A is 21.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, in which case all 14 terms are equal.

Now let's see whether we can change one of the numbers:
7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6?
Doesn't work, because 7+7+6 = 20, and the sum of ANY 3 NUMBERS must be 21.
7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8?
Doesn't work, because 7+7+8 = 22, and the sum of ANY 3 NUMBERS must be 21.

If we change even ONE of the numbers, statement 2 is not satisfied.
The implication:
To satisfy statement 2 -- to ensure that the sum of ANY 3 NUMBERS will be 21 -- all of the numbers must be 7.
Since all of the numbers must be equal, SUFFICIENT.

The correct answer is B.

In the question stem and in the statements, I've replaced Set A with List A.
A SET is a collection of DISTINCT elements.
The GMAT typically refers to a collection of non-distinct elements as a LIST.
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by saadiagha » Thu Dec 06, 2012 4:09 pm
Hey great reply..

I have one question;

Cant the elements in a set adding up to 21 be another combination?

Example- 10+5+6?

It still adds up to 21, and its three distinct elements.

Is that a possibility?
And if we take that to be the case, then statement 2 wont be sufficient?

Thanks!

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by achal46 » Thu Dec 06, 2012 8:18 pm
Saadiagha

The Important thing to note in the 2nd statement is the word - 'ANY'. The sum of any three terms has to be 21, and this is only possible when they are all equal. If you take 5(1st term),6(2nd term),10(3rd term) as any of the terms in the series, and lets say the 4th term is 5 again, so that the sum of the next 3 is 21...now if as per the statement you pick terms 1,2 and 4 meaning 5,6, 5....the sum is not 21. So, 2nd is not satisfied. For that to happen they will all have to be equal.

Hope this helps

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by The Iceman » Thu Dec 06, 2012 9:46 pm
saadiagha wrote: Is that a possibility?
And if we take that to be the case, then statement 2 wont be sufficient?

Thanks!
Let's say the numbers in the set are denoted by a,b,c,d,e, etc.

As per question, a+b+c=a+b+d=a+b+e ... => c=d=e...

On these lines, a=b=c=d=e=...