BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Are all of the terms in Set A equal?

Expert replies
Source: — Data Sufficiency |

by GMATGuruNY » Thu Dec 06, 2012 1:42 am
himu wrote:Are all of the terms in List A equal?

The sum of all 14 terms in List A is 98.
The sum of any 3 terms in List A is 21.
Statement 1: The sum of all 14 terms in List A is 98.
Average of all 14 terms = 98/14 = 7.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, in which case all 14 terms are equal.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6, 8, in which case all 14 terms are NOT equal.
INSUFFICIENT.

Statement 2: The sum of any 3 terms in List A is 21.
It's possible that the terms are 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, in which case all 14 terms are equal.

Now let's see whether we can change one of the numbers:
7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6?
Doesn't work, because 7+7+6 = 20, and the sum of ANY 3 NUMBERS must be 21.
7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8?
Doesn't work, because 7+7+8 = 22, and the sum of ANY 3 NUMBERS must be 21.

If we change even ONE of the numbers, statement 2 is not satisfied.
The implication:
To satisfy statement 2 -- to ensure that the sum of ANY 3 NUMBERS will be 21 -- all of the numbers must be 7.
Since all of the numbers must be equal, SUFFICIENT.

The correct answer is B.

In the question stem and in the statements, I've replaced Set A with List A.
A SET is a collection of DISTINCT elements.
The GMAT typically refers to a collection of non-distinct elements as a LIST.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by saadiagha » Thu Dec 06, 2012 4:09 pm
Hey great reply..

I have one question;

Cant the elements in a set adding up to 21 be another combination?

Example- 10+5+6?

It still adds up to 21, and its three distinct elements.

Is that a possibility?
And if we take that to be the case, then statement 2 wont be sufficient?

Thanks!
Join the discussion

by achal46 » Thu Dec 06, 2012 8:18 pm
Saadiagha

The Important thing to note in the 2nd statement is the word - 'ANY'. The sum of any three terms has to be 21, and this is only possible when they are all equal. If you take 5(1st term),6(2nd term),10(3rd term) as any of the terms in the series, and lets say the 4th term is 5 again, so that the sum of the next 3 is 21...now if as per the statement you pick terms 1,2 and 4 meaning 5,6, 5....the sum is not 21. So, 2nd is not satisfied. For that to happen they will all have to be equal.

Hope this helps
Join the discussion

by The Iceman » Thu Dec 06, 2012 9:46 pm
saadiagha wrote: Is that a possibility?
And if we take that to be the case, then statement 2 wont be sufficient?

Thanks!
Let's say the numbers in the set are denoted by a,b,c,d,e, etc.

As per question, a+b+c=a+b+d=a+b+e ... => c=d=e...

On these lines, a=b=c=d=e=...
Join the discussion