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Need some help..!

Expert replies
by Hmna » Sun Apr 30, 2017 5:33 am
If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) – 4
B) – 8
C) – 10
D) – 12
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Source: — Problem Solving |

by Brent@GMATPrepNow » Sun Apr 30, 2017 6:51 am
Hmna wrote:If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) –4
B) –8
C) –10
D) –12
Given: 5M – 4N = 20
Add 4N to get: 5M = 20 + 4N
Divide by 5 to get: M = 4 + 4N/5
Factor out a 4 to get: M = 4(1 + N/5)
This tells us that M must be a multiple of 4 (it also tells us that N must be a multiple of 5, in order for N/5 to be an integer)

Since M must be a multiple of 4, we can see that the correct answer is C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by hoppycat » Wed Jun 14, 2017 8:03 am
Hmna wrote:If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) – 4
B) – 8
C) – 10
D) – 12
I tested each answer
For A I got M = -4 and N = -10
For B I got M = -8 and N = -15
For C I got M = -10 and N = -17.5 which isn't an integer
Is this a valid way to go?
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by [email protected] » Wed Jun 14, 2017 4:53 pm
Hi hoppycat,

TESTing THE ANSWERS can be a fast and easy way to tackle certain Quant questions (and you'll see at least a few opportunities on the Official GMAT to do so). And to answer your question: YES, that's a great way to approach this question.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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by Brent@GMATPrepNow » Wed Jun 14, 2017 7:42 pm
hoppycat wrote:
Hmna wrote:If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) – 4
B) – 8
C) – 10
D) – 12
I tested each answer
For A I got M = -4 and N = -10
For B I got M = -8 and N = -15
For C I got M = -10 and N = -17.5 which isn't an integer
Is this a valid way to go?
If anything, your approach might actually be faster :-)
Brent Hanneson - Creator of GMATPrepNow.com
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by Jay@ManhattanReview » Wed Jun 14, 2017 9:05 pm
Hmna wrote:If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) – 4
B) – 8
C) – 10
D) – 12
I think plug-in the values approach is the most efficient for this particular problem.

Here is the Algebraic route to this problem.

We have 5M – 4N = 20

=> -5|M| + 4|N| = 20; since M and N are negative integers

=> |M| = [4|N| – 20]/5

=> |M| = (4/5)*|N| – 4

Since M is an integer, (4/5)*|N| must be an integer. thus, |N| must be a multiple of 5.

Thus, N can be –5, –10, –15, –20, etc.

N ≠ –5 since this leads to |M| = 0, which is not possible as M a negative integer

For N = –10, |M| = (4/5)*|–10| – 4 = 8 – 4 = 4 => M = –4 --- Oprion A is possible
For N = –15, |M| = (4/5)*|–15| – 4 = 12 – 4 = 8 => M = –8 --- Oprion B is possible
For N = –20, |M| = (4/5)*|–20| – 4 = 16 – 4 = 12 => M = –12 --- Oprion D is possible

The correct answer: C

Hope this helps!

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-Jay
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by Scott@TargetTestPrep » Thu Jun 15, 2017 3:29 pm
Hmna wrote:If M and N are negative integers and 5M – 4N = 20, which of the following CAN NOT be a value of M?
A) – 4
B) – 8
C) – 10
D) – 12
We are given that M and N are negative integers. Let’s isolate N in the equation 5M - 4N = 20:

5M - 20 = 4N

N = (5M - 20)/4

N = 5M/4 - 5

We see that the only way N can be an integer is if M is divisible by 4 (since 5 is not divisible by 4). Looking at the choices, only -10 is not divisible by 4; thus, it cannot be a value of M.

Answer: C

Scott Woodbury-Stewart
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by Matt@VeritasPrep » Thu Jun 22, 2017 5:49 pm
5M - 4N = 20

5M = 20 + 4N

5M = 4 * (5 + N)

Now we can use a neat trick. Since 5M = some multiple of 4, we know that 5M is a multiple of 4. Since 5 contains no prime factors of 4, we can say that M must contain them, so M = some multiple of 4. C isn't a multiple of 4, so that CAN'T be the value of M.
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