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Need Help ..pls give answer with justification

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by jeegarm » Sat Oct 04, 2008 3:40 am
Q32:
If xyz ≠ 0, is x (y + z) = 0?
(1) ¦y + z¦ = ¦y¦ + ¦z¦
(2) ¦x + y¦ = ¦x¦ + ¦y¦
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Answer:
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by krazy800 » Sat Oct 04, 2008 5:25 am
Ans is A

Given that XYZ#0.. therefore neither of the numbers are zero

Statement 1: Mod(y+z) = Mod(y) + Mod(z).. This can be possible only when both Y and Z are either positive or negative numbers.

therefor the summation i.e. (Y+Z#0)

this clubbed up with xyz#0, would be sufficent to determine that X*(Y+Z)#0

Statement 2:Though we can arrive that x,y,z are non zero and that X+Y#0.. no conclusion can be arrived if (Y+Z=0 or not) using this case.. therefore
statement 2 is not sufficent.
Aiming High
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by jeegarm » Sat Oct 04, 2008 6:11 pm
The answer for this is given to be C ...please let me know how is it possible because i have also marked A
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Re: Need Help ..pls give answer with justification

by Morgoth » Sat Oct 04, 2008 11:53 pm
jeegarm wrote:Q32:
If xyz ≠ 0, is x (y + z) = 0?
are you sure the question is x (y + z) = 0?

I doubt the answer would be C if this is posted correctly.
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