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need help---- OG 13, PS - 196

Problem Solving — algebra and arithmetic
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by Win_the_gmat » Wed Apr 17, 2013 2:43 pm
From the consecutive integers -10 to 10, inclusive, 20 integers are randomly chosen with repetitions allowed.What is the least possible value of the product of the 20 integers?
Ans : -(10)^20
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by Zarrolou » Wed Apr 17, 2013 3:31 pm
The least possible value should be as big as possible and negative.

The biggest value is obtain through the moltiplication of the biggest values (-10,10)
If we pick -10 x20 times however the result will be positive, and we don't want that.
So we have to make sure to pick for example 19 times -10 and one time 10 (or x19 10 and x1 -10), so the resulting sign will be negative.
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by Anju@Gurome » Wed Apr 17, 2013 7:35 pm
Win_the_gmat wrote:From the consecutive integers -10 to 10, inclusive, 20 integers are randomly chosen with repetitions allowed.What is the least possible value of the product of the 20 integers?
We need to select 20 integers such that their product is lowest.
The biggest value we can obtain is 10^20 but that will be a positive number. If we can somehow make it negative, it'll be the smallest possible product. We can make it negative, if we multiply odd number of 10s and odd number of -10s. For example, one 10 and nineteen -10 or three 10 and seventeen -10 etc.

Hence, least possible product = 10*[(-10)^19] = -(10)*(10^19) = -(10^20)
Anju Agarwal
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