$$check\ if\ \ \frac{n\left(n+1\right)\left(n+2\right)}{4}$$
n (n+1) (n+2) is the product of three consecutive integers.
The product of three consecutive integers is always divisible by 2 and 3 because the product of k consecutive integers is always divisible by k!
Statement 1
n is an even integer.
if n is an even integer, then n (n+1) (n+2) will be product of three consecutive integers that will be divisible by the multiple of 2
if n = 2
$$\frac{2\left(2+1\right)\left(2+2\right)}{4}$$
$$\frac{2\cdot3\cdot4}{4}=\frac{24}{4}=6$$
Hence, n (n+1) (n+2) will always be even if n is an even integer ;
Statement 1 is INSUFFICIENT.
Statement 2
$$1238\le n\le1240$$
$$hence,\ n\le1239$$
$$1239\ is\ a\ multiple\ of\ \ 3,\ hence\ n\left(n+1\right)\left(n+2\right)\ is\ divisible\ by\ 4$$
$$\frac{1239\left(1239+1\right)\left(1239+2\right)}{4}$$
$$\frac{1239\left(1240\right)\left(1241\right)}{4}$$
$$\frac{1906622760}{4}$$
$$476655690\ which\ is\ an\ even\ integer\ $$
statement 2 is INSUFFICIENT.
$$answer\ is\ Option\ D$$