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Multiples

Expert replies
by binaras » Wed Apr 01, 2015 11:11 pm
Hi

need some help with the following

If n is a multiple of 5 and n = p squared x q, where p & q are prime numbers which of the following must be a multiple of 25?
1. p squared
2. q squared
3. pq
4. p squared x q squared
5. p cubed x q

Thanks
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Source: — Problem Solving |

by GMATGuruNY » Thu Apr 02, 2015 12:40 am
If n is a multiple of 5 and n = p^2q, where p and q are prime numbers, which of the following must be a multiple of 25?
a. p^2
b. q^2
c. pq
d. P^2q^2
e. p^3q
When a question asks WHICH OF THE FOLLOWING MUST BE X?, try to prove that four of the answer choices DO NOT HAVE TO BE X.

In order for n to be a multiple of 5, either p and/or q must be a multiple of 5.
Since the goal is to prove that four of the answer choices do NOT have to be divisible by 25, test the SMALLEST POSSIBLE COMBINATIONS.

Case 1: Let p=2 and q=5, with the result that n = 2²(5) = 20.

A) p² = 2² = 4. Not a multiple of 25. Eliminate A.
B) q² = 5² = 25. 25 is a multiple of 25. Hold onto B.
C) pq = 2*5 = 10. Not a multiple of 25. Eliminate C.
D) p²q² = 2²(5²) = 100. 25 is a multiple of 25. Hold onto D.
E) p³q = (2³)5 = 40. Not a multiple of 25. Eliminate E.

Case 2: Let p=5 and q=2, with the result that n = (5²)2 = 50.
B) q² = 2² = 4. Not a multiple of 25. Eliminate B.

The correct answer is D.
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by Brent@GMATPrepNow » Thu Apr 02, 2015 5:48 am
If n is multiple of 5, and n = p²q, where p and q are prime numbers, which of the following MUST be a multiple of 25?

A) p²
B) q²
C) pq
D) p²q²
E) p³q
If p and q are prime numbers, and p²q is divisible by 5, then either p = 5, q = 5 or they both equal 5.

We're looking for an expression that MUST be divisible by 25, which means there must be TWO 5's "hiding" in the expression.

A) p²
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 2 and q = 5, in which case p² is NOT divisible by 25
ELIMINATE A

B) q²
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 5 and q = 2, in which case q² is NOT divisible by 25
ELIMINATE B

C) pq
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 5 and q = 2, in which case pq is NOT divisible by 25
ELIMINATE C

D) p²q²
YES, we can be certain that there are TWO 5's "hiding" in this expression.
If p = 5, then p²q² = 25q², which is DEFINITELY divisible by 25
If q = 5, then p²q² = 25p², which is DEFINITELY divisible by 25

E) p³q
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 2 and q = 5, in which case p³q is NOT divisible by 25
ELIMINATE E

Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by binaras » Thu Apr 23, 2015 2:43 am
thanks for the reply
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