Absolute Value Question

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Absolute Value Question

by anwarma » Wed Jun 11, 2008 4:06 pm
If y is an integer, then the least possible value of | 23 - 5y | is

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

ANS is B

so how do I apply Absolute value concept to find the least value? Can someone direct me?
AA
Source: — Problem Solving |

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by litteraround » Wed Jun 11, 2008 4:18 pm
23-5y is smallest when y=5. so 23-5y becomes 23-5(5) = -2. Now, since it is , as per the question, l-2l, it is the same as 2. (Absolute value is the pure form of any integer, without it being negative (or positive)).

So, the answer is 2.

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by anwarma » Wed Jun 11, 2008 5:13 pm
Thanks!
AA