Stmt I

Stmt I

1 2 2 2 3 YES

0 0 0 2 3 NO

Stmt II

1 2 2 2 3 YES

0 0 0 2 3 NO

Together:

1 2 2 2 3 YES

0 0 0 2 3 NO

ISNUFF

Choose E

"The only part I am wondering is the " If the mode of the 5 numbers is unique"-> What does it mean unique since mode means it has to occur atleast twice in a set of 5 numbers if the other 3 are distinct/unique to be a mode in the first place"


Regards,
CR

A non-unique mode would look like this:
(1,2,2,3,3) there are two distinct modes.

When it mentions a unique mode, it's simply telling us that there is only one value for the mode. So more specifically, for all values of the set that are not = mode, they can only be equal to each other in lower frequency than the mode...
(1,1,2,2,2)
(1,2,3,3,4)

Thanks Buckeye! Missed that part (bimodal)

Regards,
CR

Can someone explain why NOT (B) ?

Bidisha_800-

We're asked to determine if the mode of a set is equal to the mean. The mode is the most frequent member of the set (in this case it is unique - which means there is only one mode). The mean is the average of all the members of the set.

(2) Tells us that three of the five set members are the same. Obviously, this value will also be the mode (as the most frequent member).

So, let's suppose (as cramya wrote) that the set is...
{1,2,2,2,3}
This set meets the requirement of a unique mode = 2. It also meets the requirement of (2) in that three of the five are the same {2,2,2}.

The average of this set is (1+2+2+2+3)/5 = 10/5 = 2.

So, the mean and mode are equal. BUT, are they equal for all possible sets under condition (2)?

Let's suppose (thanks to cramya again) that the set is...
{0,0,0,2,3}
Mode = 0. Three of five are the same {0,0,0}.

The average of this set is (0+0+0+2+3)/5 = 5/5 = 1.

So, the mean and mode are NOT equal. So, we cannot determine conclusively that the mode will equal the mean when three members of the set are the same.

(2) is Insufficient.

Hope that helps.

BuckeyeT wrote:Bidisha_800-

We're asked to determine if the mode of a set is equal to the mean. The mode is the most frequent member of the set (in this case it is unique - which means there is only one mode). The mean is the average of all the members of the set.

(2) Tells us that three of the five set members are the same. Obviously, this value will also be the mode (as the most frequent member).

So, let's suppose (as cramya wrote) that the set is...
{1,2,2,2,3}
This set meets the requirement of a unique mode = 2. It also meets the requirement of (2) in that three of the five are the same {2,2,2}.

The average of this set is (1+2+2+2+3)/5 = 10/5 = 2.

So, the mean and mode are equal. BUT, are they equal for all possible sets under condition (2)?

Let's suppose (thanks to cramya again) that the set is...
{0,0,0,2,3}
Mode = 0. Three of five are the same {0,0,0}.

The average of this set is (0+0+0+2+3)/5 = 5/5 = 1.

So, the mean and mode are NOT equal. So, we cannot determine conclusively that the mode will equal the mean when three members of the set are the same.

(2) is Insufficient.

Hope that helps.

sorry, I read the question incorrectly. I thought it is asking whether mode = median
I re-read and found it is asking mode= mean