Vincen Legendary Member View User Profile Posts: 2898 Joined: Thu Sep 07, 2017 2:49 pm Thanked: 6 times Followed by:5 members \(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\) by Vincen » Mon Nov 09, 2020 7:48 am Timer 00:00 Your Answer A B C D E Global Stats \(\dfrac{(x^4y^3)^{-2}}{(x^3y^2)^{-4}}=\) A. \(x^{-4}y^{-2}\) B. \(xy\) C. \(x^3y^3\) D. \(x^2y^2\) E. \(x^4y^2\) Answer: E Source: Veritas Prep Top Quote
