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by stubbornp » Sun Oct 19, 2008 11:53 pm
please explain
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by vittalgmat » Mon Oct 20, 2008 12:06 am
Answer is 25 factors.

36^2 = (3^2 * 2^2) ^2
= 3^4 * 2^4

The # of factors is (4+1) * (4+1) = 25.

PS: there is a nice explanation on how to find total # of factors by either Ian or Stuart.

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by stop@800 » Mon Oct 20, 2008 3:35 am
vittalgmat wrote:Answer is 25 factors.

36^2 = (3^2 * 2^2) ^2
= 3^4 * 2^4

The # of factors is (4+1) * (4+1) = 25.

PS: there is a nice explanation on how to find total # of factors by either Ian or Stuart.
vittalgmat, do we have any other explanation also, than one you mentioned?
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by mental » Wed Oct 22, 2008 10:06 am
PS: there is a nice explanation on how to find total # of factors by either Ian or Stuart.

can anyone pls post the link ------
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by jayjk78 » Thu Oct 23, 2008 5:49 pm
Find the primes for 36 (3^2 and 2^)^2 That is 3^4 2^4

Now the primes will be

1, 2,2^2,2^3,2^4,3,3^2,3^3,3^4 =9 primes and combination of (2,2^2,2^3,2^4,3,3^2,3^3,3^4) that is 4*4=16

9+16 = 25
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by Delpaiero » Sat Oct 25, 2008 2:56 am
The explanation of this formula is on a following link. I found it on Google. You guys check it out.

https://mathforum.org/library/drmath/view/57151.html
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