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divisors of product of prime numbers

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by krishnasty » Fri Jul 22, 2011 10:40 pm
If pand qare prime numbers, how many divisors does the product (p^3)(q^6) have?

(A) 9
(B) 12
(C) 18
(D) 28
(E) 363


OA : D
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by top_business_2011 » Fri Jul 22, 2011 11:13 pm
krishnasty wrote:If pand qare prime numbers, how many divisors does the product (p^3)(q^6) have?

(A) 9
(B) 12
(C) 18
(D) 28
(E) 363


OA : D
To find the number of divisors for a number expressed in the form of its prime factors, one has to add 1 to the powers of each prime factor and multiply the resulting values altogether.

(p^3)(q^6)

The number of divisors or factors = (3+1)* (6+1)
= 4 *7 = 28
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by GMATGuruNY » Sat Jul 23, 2011 1:53 am
I posted a solution here:

https://www.beatthegmat.com/divisors-t85731.html
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