If p and q are prime numbers, how many divisors does the product P^3 *q^6 have?
(A) 9
(B) 12
(C) 18
(D) 28
(E) 36
Divisors
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Hi,
if a number N = a^p. b^q.c^r.... where a,b,c are prime factors, then the number of factors is given by:
(p+1)*(q+1)*(r+1)*...
Here the number is p^3*q^6
So, number of factors is (3+1)8(6+1) = 28
Hence, D
if a number N = a^p. b^q.c^r.... where a,b,c are prime factors, then the number of factors is given by:
(p+1)*(q+1)*(r+1)*...
Here the number is p^3*q^6
So, number of factors is (3+1)8(6+1) = 28
Hence, D
Cheers!
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Things are not what they appear to be... nor are they otherwise
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Thanks man. Does this formula apply to finding the factors in general? Like when you do prime factorization you can use it then to find the factors?Frankenstein wrote:Hi,
if a number N = a^p. b^q.c^r.... where a,b,c are prime factors, then the number of factors is given by:
(p+1)*(q+1)*(r+1)*...
Here the number is p^3*q^6
So, number of factors is (3+1)8(6+1) = 28
Hence, D
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Yes. That is my purpose of writing the formula. I have mentioned about the prime factors thing as well.MBA.Aspirant wrote: Thanks man. Does this formula apply to finding the factors in general? Like when you do prime factorization you can use it then to find the factors?
Cheers!
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Things are not what they appear to be... nor are they otherwise
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It might be helpful to understand the reasoning behind the formula offered by Frankenstein.MBA.Aspirant wrote:Thanks man. Does this formula apply to finding the factors in general? Like when you do prime factorization you can use it then to find the factors?Frankenstein wrote:Hi,
if a number N = a^p. b^q.c^r.... where a,b,c are prime factors, then the number of factors is given by:
(p+1)*(q+1)*(r+1)*...
Here the number is p^3*q^6
So, number of factors is (3+1)8(6+1) = 28
Hence, D
To determine the number of positive factors of an integer:
1) Prime-factorize the integer
2) Add 1 to each exponent
3) Multiply
For example:
72 = 2³ * 3².
Adding 1 to each exponent and multiplying, we get (3+1)*(2+1) = 12 factors.
Here's why:
To determine how many factors can be created from 72 = 2³ * 3², we need to determine the number of choices we have of each prime factor and to count the number of ways these choices can be combined:
For 2, we can use 2�, 2¹, 2², or 2³, giving us 4 choices.
For 3, we can use 3�, 3¹, or 3², giving us 3 choices.
Multiplying the number of choices we have of each factor, we get 4*3 = 12 possible factors.
Regarding the following question:
The question needs to say that p and q are distinct prime numbers and that we are to count the number of positive divisors. Assuming p and q are distinct, we add 1 each exponent and multiply:If p and q are prime numbers, how many divisors does the product P^3 *q^6 have?
(A) 9
(B) 12
(C) 18
(D) 28
(E) 36
(3+1)(6+1) = 4*7 = 28.
If p and q are not distinct, then p³q� = p³p� = p�, yielding only 9+1 = 10 factors.
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Thanks GMATGuru for your help. The part about the non-distinct factors was very helpful. I just faced it with 64 where the factors are/is 2^6. the number of factors then is (6+1) not (3+1) * (3+1)GMATGuruNY wrote:It might be helpful to understand the reasoning behind the formula offered by Frankenstein.MBA.Aspirant wrote:Thanks man. Does this formula apply to finding the factors in general? Like when you do prime factorization you can use it then to find the factors?Frankenstein wrote:Hi,
if a number N = a^p. b^q.c^r.... where a,b,c are prime factors, then the number of factors is given by:
(p+1)*(q+1)*(r+1)*...
Here the number is p^3*q^6
So, number of factors is (3+1)8(6+1) = 28
Hence, D
To determine the number of positive factors of an integer:
1) Prime-factorize the integer
2) Add 1 to each exponent
3) Multiply
For example:
72 = 2³ * 3².
Adding 1 to each exponent and multiplying, we get (3+1)*(2+1) = 12 factors.
Here's why:
To determine how many factors can be created from 72 = 2³ * 3², we need to determine the number of choices we have of each prime factor and to count the number of ways these choices can be combined:
For 2, we can use 2�, 2¹, 2², or 2³, giving us 4 choices.
For 3, we can use 3�, 3¹, or 3², giving us 3 choices.
Multiplying the number of choices we have of each factor, we get 4*3 = 12 possible factors.
Regarding the following question:
The question needs to say that p and q are distinct prime numbers and that we are to count the number of positive divisors. Assuming p and q are distinct, we add 1 each exponent and multiply:If p and q are prime numbers, how many divisors does the product P^3 *q^6 have?
(A) 9
(B) 12
(C) 18
(D) 28
(E) 36
(3+1)(6+1) = 4*7 = 28.
If p and q are not distinct, then p³q� = p³p� = p�, yielding only 9+1 = 10 factors.