BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

MGMAT DS

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 21
Joined: Thu May 15, 2008 12:51 am
Thanked: 1 times

by bharathaitha » Thu Oct 23, 2008 5:01 am
The expression (K+2)(K^2+4K+3) can be reduced to

(K+2)(K+1)(K+3) ==> (K+1)(K+2)(K+3)

Statement A

K/8 is an integer i.e. k= 8, 16, 24, 32, 40, 48 etc. for all those values (K+1)(K+2)(K+3) is not divisible by 4

Hence SUFFICIENT

Statement B

(K+1)/3 is an odd integer, then K = 2, 8, 14, 20

For K = 8, (K+1)(K+2)(K+3) is not divisible by 4
For K = 14, (K+1)(K+2)(K+3) is divisible by 4

Hence INSUFFICIENT

Therefore the OA is A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Fri Jul 18, 2008 11:15 pm

Re: MGMAT DS

by drpawan » Thu Oct 23, 2008 5:16 am
PAB2706 wrote:For positive integer k, is the expression (k + 2)(k^2 + 4k + 3) divisible by 4?

(1) k is divisible by 8.

(2) k + 1/3 is an odd integer.

not understanding the approach to this problem
Same explanation as bharathaitha.
ans is A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Thu Oct 23, 2008 6:12 am
A different explanation but answer is A :)


A
K is divisible by 8
hence
K is divisible by 4
so
K+2 will not be divisible by 4 but will be divisible by 2

As
K is divisible by 8
we know k is even
so
(k^2 + 4k + 3)
will be odd
and odd no can never be divisible by 2
hence
(k + 2)(k^2 + 4k + 3) will not be divisible by 4
Sufficient


B
PS: I assumed k + 1/3 to be (k + 1)/3
since former does not make sense at all
it can not be an interger.

(k + 1)/3 is an odd integer
means
K is even
so K is divisible by 2
but we can not conclude about 4

so
K+2 also even and also divisible by 2
but we can not conclude about 4


K even so
(k^2 + 4k + 3) odd
hence we can not conclude whether exp is divisible by 4 or not
Insuff


Hope this helps
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Thu Oct 23, 2008 1:24 pm
Explaining a little further


(k + 2)(k^2 + 4k + 3)

If u break down k^2+4k+3 u will get (k+1) (k+3)

So basically the question boils down to Is (k+1)(k+2)(k+3) is divisible by 4?

Stmt I) Given k is divisible by 8

It takes k+4 for the next number to be divisible by 4. Hence we can certainly conclude that (k+1)(k+2)(k+3) since its given k is divisible by 8


Eg: If k=8 it will be 9*10*11 - not divisible by 4

Stmt 2) k+1/3 is odd

3k+1/3 = odd
3k+1 = 3*odd

3*odd is odd(odd*odd = odd)

So 3k+1 is odd
In this 1 is odd so 3k has to be even(since odd+odd will give u even)
In 3k, 3 is odd for 3k to be even k has to be even(since odd*odd=odd whereas odd*even = even)

All we know is k is even

If k is 4 then (k+1)(k+2)(k+3) = 5*6*7 - Not divisible by 4
If k=2 (k+1)(k+2)(k+3) 3*4*5 - divisible by 4

INSUFFICEINT

Hence A)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Thu Oct 23, 2008 1:27 pm
ADDITIONS IN BOLD:

Explaining a little further


(k + 2)(k^2 + 4k + 3)

If u break down k^2+4k+3 u will get (k+1) (k+3)

So basically the question boils down to Is (k+1)(k+2)(k+3) divisible by 4?

Stmt I) Given k is divisible by 8

It takes k+4 for the next number to be divisible by 4. Hence we can certainly conclude that (k+1)(k+2)(k+3) is not divisible by 4 since its given k is divisible by 8

SUFFICIENT

Eg: If k=8 it will be 9*10*11 - not divisible by 4

Stmt 2) k+1/3 is odd

3k+1/3 = odd
3k+1 = 3*odd

3*odd is odd(odd*odd = odd)

So 3k+1 is odd
In this 1 is odd so 3k has to be even(since odd+odd will give u even)
In 3k, 3 is odd for 3k to be even k has to be even(since odd*odd=odd whereas odd*even = even)

All we know is k is even

If k is 4 then (k+1)(k+2)(k+3) = 5*6*7 - Not divisible by 4
If k=2 (k+1)(k+2)(k+3) 3*4*5 - divisible by 4

INSUFFICIENT

Hence A)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 65
Joined: Sun Oct 19, 2008 2:18 pm
Thanked: 1 times

Re: MGMAT DS

by yezz » Thu Oct 23, 2008 1:53 pm
For positive integer k, is the expression (k + 2)(k^2 + 4k + 3) divisible by 4?

(1) k is divisible by 8.

(2) k + 1/3 is an odd integer.

(k+2)(k+3)(k+1) ie: 3 consecutive intigers

in any 3 consecutive intigers ( devisiable by 4 if 2 of them r even or the midlle one is devisable by 4.

from one

if k is divisible by 8 , thus k+2 is even AND IMPOSSIBLE TO BE DEVISBLE BY 4

TRY ALL MULTIPLES OF 8X +2

from 2

k+1 = odd ie: k is even,, however we have no clue if (k+2 is a multiple of 4)

both

insuff.....A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 541
Joined: Thu May 31, 2007 6:44 pmFollowed by: 3 members
Location: UK
Thanked: 21 times
GMAT Score:680

by rohangupta83 » Thu Oct 23, 2008 2:43 pm
good to see so many different approaches. imo A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1