BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT PrepTest Question

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Wed Apr 16, 2008 1:58 am
by jjw.ashish » Thu May 22, 2008 3:11 am
Hi ,

For the question attached ,

The correct answer is option C II only.

I couldn't figure it how .

Suppose I take x = 16 , y = 9

sq root of x can be +4 , -4 . I choose -4
sq root of y can be +3 , -3 . I choose -3.

Now the equation becomes -7/25 which is less than 1/sq root of (x + y )
If I take sq root values as +ve then it becomes greater than 1/sq root of (x + y)

So I am getting two answers .

Is my logic flawed ? Please let me know .
Attachments
GMAT-DS.JPG
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Master | Next Rank: 500 Posts
Posts: 192
Joined: Tue Apr 29, 2008 7:41 am
Thanked: 14 times

by aatech » Thu May 22, 2008 5:45 am
I think you missed the part where it says x and y are +ve
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 294
Joined: Tue Feb 26, 2008 9:05 pmFollowed by: 1 member
Thanked: 13 times

by amitansu » Fri May 23, 2008 12:51 am
Is it C i.e II only..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 171
Joined: Sat May 03, 2008 3:51 pm
Thanked: 8 times

by wawatan » Fri May 23, 2008 1:03 am
the answer is c.

try manipulating the equation . ...i will post explanation later
Last edited by wawatan on Fri May 23, 2008 1:41 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 294
Joined: Tue Feb 26, 2008 9:05 pmFollowed by: 1 member
Thanked: 13 times

by amitansu » Fri May 23, 2008 1:10 am
I basically tried multiplying sqrt (x+y) to numerator for each of the given
data.
That makes q data is 1.

And then comparing whether 1 is greater than any of the given data..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1