BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Means of lists of odd and even integers

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Tue Nov 08, 2011 4:42 am
by jzebra10 » Sun Nov 20, 2011 1:41 am
Please help. I don't know how to solve.

List S consists of 10 consecutive odd integers, and like T consists of 5 consecutive even integers. If the least integer in S is 7 more than the least integer in T, how much greater is the average of the integers in S that the average of the integers in T?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 158
Joined: Sat Sep 03, 2011 10:31 amFollowed by: 2 members
Thanked: 29 times

by gmatclubmember » Sun Nov 20, 2011 1:59 am
List S=m+7,m+9,...,m+25
T = m,m+2,m+4,...,m+8.
Avg(S)=m+16 and Avg(T)=m+4
Avg of S is 12 more than avg of T.
a lil' Thank note goes a long way :)!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sun Nov 20, 2011 4:15 am
jzebra10 wrote:Please help. I don't know how to solve.

List S consists of 10 consecutive odd integers, and like T consists of 5 consecutive even integers. If the least integer in S is 7 more than the least integer in T, how much greater is the average of the integers in S that the average of the integers in T?
When numbers are evenly spaced, THE AVERAGE = THE MEDIAN.
Let T = 2,4,6,8,10.
Average = median = 6.

The least value in S = 2+7 = 9.
S = 9,11,13,15,17,19...
Average = median = (17+19)/2 = 18.

Average in S - average in T = 18-6 = 12.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1